\(\frac{3}{4}+\frac{1}{4}:X=-3=>\frac{1}{4}:X=-3-\frac{3}{4}\)
\(=>\frac{1}{4}:X=\frac{-15}{4}=>X=\frac{1}{4}:\frac{-15}{4}\)
\(=>X=\frac{-1}{5}.\)
\(\frac{3}{4}+\frac{1}{4}:X=-3=>\frac{1}{4}:X=-3-\frac{3}{4}\)
\(=>\frac{1}{4}:X=\frac{-15}{4}=>X=\frac{1}{4}:\frac{-15}{4}\)
\(=>X=\frac{-1}{5}.\)
1, Tính \(\frac{1}{2}-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{1}{4}+\frac{2}{4}+\frac{3}{4}\right)-\left(\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}\right)+...+\left(\frac{1}{100}+\frac{2}{100}+\frac{3}{100}+...+\frac{99}{100}\right)\)2,Tính \(\left(1-\frac{1}{2^2}\right)x\left(1-\frac{1}{3^2}\right)x\left(1-\frac{1}{4^2}\right)x...x\left(1-\frac{1}{n^2}\right)\)
Bài 1 : Tính :
B = \(\frac{\frac{1}{2}+\frac{3}{4}-\frac{5}{6}}{\frac{1}{4}+\frac{3}{8}-\frac{5}{12}}+\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{8}}{\frac{1}{4}+\frac{1}{5}-\frac{1}{8}}\)
Bài 2 : tìm x và y
a) x3 - 36x = 0
b) \(\frac{x-3}{y-2}=\frac{3}{2}\)và x - y = 4 ( x , y \(\in\)Z )
Bài 1:Tìm \(x\in Z\)biết
\(A=\frac{3}{x-1}\)\(B=\frac{x-2}{x+3}\)\(C=\frac{2x+1}{x-3}\)
Bài 2:Chứng tỏ rằng:
\(A=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{63}>2\)\(B=\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+\frac{1}{6^2}+\frac{1}{7^2}+\frac{1}{8^2}< 1\)
Bài 3:Tính hợp lí
\(A=\frac{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{11}}\)
\(B=\frac{7}{4}\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
Tính:\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
Bài 1:tính nhanh
a. 6\(\frac{4}{5}\)-\(\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
b. \(7\frac{5}{9}-\left(2\frac{3}{4}+3\frac{5}{9}\right)\)
c. \(\frac{-3}{5}.\frac{5}{7}+\frac{-3}{5}.\frac{3}{7}+\frac{-3}{5}.\frac{6}{7}\)
d. \(\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}-\frac{4}{3}\)
Bài 2: tìm x
a. \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
b. \(x+30\%x=-1,3\)
c. \(3\frac{1}{3}x+16\frac{3}{4}=-13,25\)
d. \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
e. |2x-1|=\(\left(-4\right)^2\)
gấp nha các bạn !!!!!!!!
Bài 1: Tính
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{3}.0,38\right)\right]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
Bài 2: Tìm x
\(\frac{-15}{12}.x+\frac{3}{7}=\frac{6}{5}.x-\frac{1}{2}\)
Tính:
\(\frac{\frac{1}{3}+\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}+\frac{4}{14}-\frac{2}{13}}\) x \(\frac{\frac{3}{4}-\frac{3}{16}+\frac{3}{64}-\frac{3}{256}}{1-\frac{1}{4}+\frac{1}{16}-\frac{1}{64}}\) + \(\frac{5}{8}\)
GIÚP MÌNH VỚI. MÌNH CẦN GẤP!
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
Bài 1. Tính:
a) (2008.2009.2010.2011).\(\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)
Bài 2. Tìm x biết:
a)\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{2}{x\left(x+1\right)}=\frac{2011}{2013}\)
b)\(\frac{1}{2}.\frac{1}{3}.\frac{1}{4}.\frac{1}{5}.\frac{1}{6}.\left(x-1,010\right)=\frac{1}{360}-\frac{1}{720}\)