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Các câu hỏi tương tự
\(A=\frac{3}{2^2}.\frac{8}{3^2}\frac{15}{4^2}.....\frac{899}{30^2}\)
Rút gọn:
\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{899}{30^2}\)
\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{899}{30^2}\)
\(A=\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}.\frac{24}{5^2}.....\frac{899}{30^2}\)
\(A=\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}.....\frac{899}{30^2}\)
\(\frac{3}{2^2}\cdot\frac{8}{32}\cdot\frac{15}{4^2}\cdot......\cdot\frac{899}{30^2}\)
Bài 1 : tính
a) \(\frac{3}{2^2}\cdot\frac{8}{3^2}\cdot\frac{15}{4^2}\cdot...\cdot\frac{899}{30^2}\)
b) \(\frac{\left(\frac{3}{4}+\frac{3}{7}-\frac{3}{8}\right)}{\frac{5}{4}+\frac{5}{7}-\frac{5}{8}}\)
Tính tích:
\(A=\frac{3}{\sqrt[2]{2}}x\frac{8}{\sqrt[2]{3}}x\frac{15}{\sqrt[2]{4}}x\frac{24}{\sqrt[2]{5}}x....x\frac{899}{\sqrt[2]{30}}\)
Tính: \(\frac{3}{2^{^2}}\)x\(\frac{8}{3^{^2}}\)x\(\frac{15}{4^{^2}}\)x..............\(\frac{899}{30^{^2}}\)