\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{8}{22}\)
\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\)
\(\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\)=\(\frac{8}{22}=\frac{4}{11}\)
Hok tốt
\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\) = \(\frac{2^5.7+2^5.1}{2^5.5^2-2^5.3}\)
= \(\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\)
= \(\frac{8}{22}\)= \(\frac{4}{11}\)
\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\)
\(=\frac{2^5.8}{2^5.22}\)
\(=\frac{8}{22}\)
\(=\frac{4}{11}\)
Study well ! >_<