Question

tính:                \(\frac{21}{54}\)+\(\frac{3}{75}\):\(\frac{\left(\frac{39}{65}\right)+0,145-\frac{33}{600}:\frac{21}{9}}{7^2-18,25+3\frac{15}{36}-16\frac{17}{102}}\)

         đóng ngoặc tron ở p/s 39/65 va 33/600

giúp mk nhé

Answer 1

21/54 + 3/75 :  (39/65) + 29/200 - ( 33/600 ) : 21/9 / 7^2 - 73/4 + 41/12 - 97/6 

= 21/54 + 3/75 :  (39/65) + 29/200 - 33/600 . 9/21 / 49 - 73/4 + 41/12 - 97/6

= 21/54 + 3/75 : 149/200 - 33/1400 / 49 - 73/4 + ( -51/4 )

= 21/54 + 3/75 : 101/140 / 123/4 + ( -51/4 )  

= 21/54 + 3/75 : 101/140 /  18

= 21/54 + 3/75 : 101/140 . 1/18

= 21/54 + 3/75 : 101/2520

= 21/54 + 3/75 . 2520/101

= 21/54 + 504/505

Answer 2

Tim hai so tu nhiên a,b  toa man dieu kien a+2b=48 va (a,b)+3=144