Question

tinh \(\frac{1}{\sqrt{2}-\sqrt{3}}.\sqrt{\frac{3\sqrt{2}-2\sqrt{3}}{3\sqrt{2}+2\sqrt{3}}}\)                                                                                    giup mik fai nop gap

Answer 1

sau khi trục căn thức ta có:

\(\left(-\sqrt{2}-\sqrt{3}\right).\frac{\left(3\sqrt{2}-2\sqrt{3}\right)}{\sqrt{6}}=\frac{-\sqrt{6}}{\sqrt{6}}\)

vậy KQ là -1 nha

Answer 2

\(=\frac{1}{\sqrt{2}-\sqrt{3}}.\sqrt{\frac{\sqrt{6}\left(\sqrt{3}-\sqrt{2}\right)}{\sqrt{6}\left(\sqrt{3}+\sqrt{2}\right)}}\)

\(=\frac{1}{\sqrt{2}-\sqrt{3}}.\sqrt{\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}}\) ?????