Question

Tính 

\(\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+...+\frac{1}{\sqrt{899}+\sqrt{900}}\)

Answer 1

\(\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+.....+\frac{1}{\sqrt{899}+\sqrt{900}}\)

=\(\frac{\sqrt{1}-\sqrt{2}}{1-2}+\frac{\sqrt{2}-\sqrt{3}}{2-3}+....+\frac{\sqrt{899}-\sqrt{900}}{899-900}\)

\(=\frac{\sqrt{1}-\sqrt{2}}{-1}+\frac{\sqrt{2}-\sqrt{3}}{-1}+....+\frac{\sqrt{899}-\sqrt{900}}{-1}\)

\(=\frac{\sqrt{1}-\sqrt{2}+\sqrt{2}-\sqrt{3}+....+\sqrt{899}-\sqrt{900}}{-1}\)

\(=\frac{\sqrt{1}-\sqrt{900}}{-1}\)

\(=\frac{1-30}{-1}=\frac{-29}{-1}=29\)

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