Lời giải:
Gọi biểu thức là $A$.
\(A=\frac{(2^4)^3.3^{10}+2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{11}.3^{11}}\\ =\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}(2.3+1)}\\ =\frac{2^{12}.3^{10}(1+5)}{7.2^{11}.3^{11}}=\frac{2^{12}.3^{10}.2.3}{7.2^{11}.3^{11}}\\ =\frac{2^{13}.3^{11}}{7.2^{11}.3^{11}}=\frac{2^2}{7}=\frac{4}{7}\)
tính:\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
Tính: A= \(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
Tính
\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
Thực hiện phép tính : \(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
16^3.3^10+120.6^9/4^6.3^12+6^11
thực hiện phép tính
A=\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}+\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{12}}\)
thực hiện phép tính
A=\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}+\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{12}}\)
a) so sánh 2 số : \(3^{30}và5^{20}\)
b) tính: A=\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
1.Tính
a)\(\frac{0,4+\frac{2}{9}-\frac{2}{11}}{1,6+\frac{8}{9}-\frac{8}{11}}\)
b)\(\frac{1}{99.97}-\frac{1}{97.95}-....-\frac{1}{5.3}-\frac{1}{3.1}\)
c)\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\)
