Question

Tính 

\(\frac{1}{2.3}+\frac{1}{3.4}+.........+\frac{1}{99.100}\)

Answer 1

Cái này mà Toán lớp 1 tui xỉu.

Mà mk làm xong h cho mk nha.

ko chep de

= 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/99 - 1/100

= 1/2 - 1/100

= 49/100

=)) tích nha : j

Answer 2

1/2*3+1/3*4+.....+1/99*100

=1/2-1/3+1/3-1/4+....+1/99-1/100

=1/2-1/100

=50/100-1/100

=49/100

Answer 3

=1/2-1/3+1/3-1/4+....+1/99-1/100

=1/2-1/100

=49/100

k cho minh nhé

Answer 4

\(\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{99x100}\)

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)

\(=\frac{1}{2}-\frac{1}{100}\)\(=\frac{49}{100}\)

Answer 5

= 1/2-1/3+1/3-1/4+1/4-..............+1/99-1/100

=1/2- 1/100

còn lạ tự tính nhé

Answer 6

1/2x3 + 1/3x4 + ... + 1/99x100

= 1/2 - 1/3 + 1/3 - 1/ 4 + ... + 1/99 - 1/100

= 1/2 - 1/100

= 49/100

Answer 7

1/2.3+1/3.4+...+1/99.100

= 1/2-1/3+1/3-1/4+...+1/99-1/100

= 1/2-1/100

=50/100-1/100

=49/100

Answer 8

=1/2-1/3+1/3-1/4+...+1/99-1/100

=1/2-1/100=50/100-1/100

=49/100

k mik nha mik k lại cho

Answer 9

1/2.3+1/3.4+...+1/99.100

=1/2-1/3+1/3-1/4+...+1/99.1/100

=1/2-1/100

=49/100

Answer 10

\(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+........+\frac{1}{99\cdot100}\)

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-........+\frac{1}{99}-\frac{1}{100}\)

\(=\frac{1}{2}-\frac{1}{100}\)

\(=\frac{50}{100}-\frac{1}{100}\)

\(=\frac{49}{100}\)

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