Các câu hỏi tương tự
Tính : P = \(\frac{\frac{1}{2003}+\frac{1}{2004}+\frac{1}{2005}}{\frac{5}{2003}+\frac{5}{2004}-\frac{5}{2005}}-\frac{\frac{2}{2002}+\frac{2}{2003}-\frac{2}{2004}}{\frac{3}{2002}+\frac{3}{2003}-\frac{3}{2004}}\)
P=\(\frac{\frac{1}{2003}+\frac{1}{2004}-\frac{1}{2005}}{\frac{5}{2003}+\frac{5}{2004}-\frac{5}{2005}}\)-\(\frac{\frac{2}{2002}+\frac{2}{2003}-\frac{2}{2004}}{\frac{3}{2002}+\frac{3}{2003}-\frac{3}{2004}}\)
Tính :
\(P=\frac{\frac{1}{2003}+\frac{1}{2004}-\frac{1}{2005}}{\frac{5}{2003}+\frac{5}{2004}-\frac{5}{2005}}-\frac{\frac{2}{2002}+\frac{2}{2003}-\frac{2}{2004}}{\frac{3}{2002}+\frac{3}{2003}-\frac{3}{2004}}\)
tinh B=\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2016}}{\frac{2016}{1}+\frac{2003}{2}+\frac{2002}{3}+...+\frac{1}{2016}}\)
tìm x biết:
\(\frac{x}{2000}+\frac{1}{500}+\frac{x}{2001}+\frac{1}{667}=\frac{x}{2002}+\frac{1}{1001}+\frac{x}{2003}+\frac{1}{2003}\)
\(\frac{y-1}{2004}+\frac{y-2}{2003}-\frac{y-3}{2002}=\frac{y-4}{2001}\)
\(x+\frac{4}{2000}+x+\frac{3}{2001}=x+\frac{2}{2002}+x+\frac{1}{2003}\)
\(x+\frac{4}{2000}+x+\frac{3}{2001}=x+\frac{2}{2002}+x+\frac{1}{2003}\)
So sánh:
a) \(\frac{2002}{2003}\) và \(\frac{2003}{2004}\)
b) \(\frac{-2002}{2003}\) và \(\frac{2005}{-2004}\)