Question

Tính :\(\frac{1}{2}\)+ \(\frac{1}{4}\)+ \(\frac{1}{8}\)+ \(\frac{1}{16}\)+  ...  +  \(\frac{1}{2048}\)

Answer 1

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{2048}\)

\(=1-\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{2048}\)

\(=1-\frac{1}{2048}\)

\(=\frac{2047}{2048}\)

Answer 2

 NHận xét :

1/2 = 1 - 1/2

1/4 = 1/2 - 1/4

1/8 = 1/4 - 1/8

...................

1/2048 = 1/1024 - 1/2048

Vậy 1/2 + 1/4 + 1/8 + ... + 1/2048

= 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + ... - ... + 1/1024 - 1/2048

= 1 - 1/2048 = 2047/2048