\(a,\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{2}{5}\)
= \(\frac{2}{5}.\frac{4}{3}+\frac{1}{3}.\frac{2}{5}=\frac{2}{5}\left(\frac{4}{3}+\frac{1}{3}\right)=\frac{2}{5}.\frac{5}{3}=\frac{2}{3}\)
b, \(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}\)
\(=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)
L-I-K-E NHA
4/5x3/4+2/5x3/4-3/4x1/5