Lời giải:
$C=(5^2-1)(5^2+1)(5^4+1)(5^8+1)(5^{16}+1)$
$=(5^4-1)(5^4+1)(5^8+1)(5^{16}+1)$
$=(5^8-1)(5^8+1)(5^{16}+1)=(5^{16}-1)(5^{16}+1)$
$=5^{32}-1$
rút gon: C=12(5^2+1)(5^4+1)(5^8+1)(5^16+1)
BT7: Tính
\(3,C=\left(5-1\right)\left(5+1\right)\left(5^2+1\right)\left(5^4+1\right)...\left(5^{16}+1\right)\)
\(4,D=15\left(4^2+1\right)\left(4^4+1\right)...\left(4^{64}+1\right)\)
\(5,E=24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)...\left(5^{128}+1\right)+\left(5^{256}-1\right)\)
Rút gọn biểu thức:
12.(52+1). (54+1). (58+1).(516+1)12.(52+1). (54+1). (58+1).(516+1)
( 5^2 + 1) ( 5^4+1) (5^8+1)(5^16 +1)(5^32 + 1)^2
Cho A=(5+1)(5^2+1)(5^4+1)(5^8+1)(5^16+1)(5^32+1) và B=1/5(5^64-1) S^2 A và B
so sánh A=5^32 -1 và B = (5^2-4.5+1)(5^2+1)(5^4 +1)(5^8+1)(5^16+1)
P=12(5^2 +1)(5^4+1)(5^8+1)(5^16+1)
so sánh 12(5^2+1)(5^4+1)(5^8+1)(5^16+1)(5^32+1) và 5^64-1
Tính:12 . (5^2 + 1) . (5^4 +1) . (5^8 +1) . (5^16 + 1)
