\(\frac{3}{7}x\frac{16}{33}+\frac{16}{33}x\frac{4}{7}\)
\(C1:=\frac{16}{77}+\frac{64}{231}=\frac{16}{33}\)
\(C2:=\frac{16}{33}\left(\frac{3}{7}+\frac{4}{7}\right)=\frac{16}{33}.1=\frac{16}{33}\)
học tốt ~~~
C1:3/7×16/33+16/33×4/7
=48/231+64/231
=112/231
C2:3/7×16/33+16/33×4/7
=16/33×(3/7+4/7)
=16/33×7/7
=113/231
C1 : \(\frac{3}{7}\times\frac{16}{33}+\frac{16}{33}\times\frac{4}{7}\)
\(=\frac{16}{77}+\frac{64}{231}\)
\(=\frac{16}{33}\)
C2 : \(\frac{3}{7}\times\frac{16}{33}+\frac{16}{33}\times\frac{4}{7}\)
\(=\frac{16}{33}\times\left(\frac{3}{7}+\frac{4}{7}\right)\)
\(=\frac{16}{33}\times1\)
\(=\frac{16}{33}\)
