\(\frac{7}{11}+\frac{3}{4}+\frac{4}{11}+\frac{1}{4}=\left(\frac{7}{11}+\frac{4}{11}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)=1+1=2\)
\(\frac{7}{11}\)+ \(\frac{3}{4}\) + \(\frac{4}{11}\) + \(\frac{1}{4}\)
= \(\left(\frac{7}{11}+\frac{4}{11}\right)\)+ \(\left(\frac{3}{4}+\frac{1}{4}\right)\)
= 1 + 1
= 2
\(\frac{72}{99}\)- \(\frac{28}{99}\) - \(\frac{14}{99}\)
= \(\frac{72}{99}\) - \(\left(\frac{28}{99}+\frac{14}{99}\right)\)
= \(\frac{72}{99}\) - \(\frac{42}{99}\)
= \(\frac{30}{99}\)
\(\frac{7}{11}+\frac{3}{4}+\frac{4}{11}+\frac{1}{4}\)
\(=\left(\frac{7}{11}+\frac{4}{11}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(=1+1=2\)
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}\)
\(=\frac{72-24-14}{99}\)
\(=\frac{34}{99}\)
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{72-\left(28+14\right)}{99}=\frac{72-42}{99}=\frac{30}{99}=\frac{10}{33}\)
mấy câu này rất dễ, bn lười nên ms k làm đc thôi
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{72-28-14}{99}=\frac{30}{99}=\frac{30\div3}{99\div3}=\frac{10}{33}\)
