a ) \(\frac{1}{15}+\frac{4}{15}+\frac{5}{18}+\frac{7}{18}\)
\(=\left(\frac{1}{15}+\frac{4}{15}\right)+\left(\frac{5}{18}+\frac{7}{18}\right)\)
\(=\frac{1}{3}+\frac{2}{3}\)
\(=1\)
b ) \(\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}\)
\(=\left(\frac{1}{8}+\frac{3}{8}\right)+\left(\frac{1}{12}+\frac{5}{12}\right)\)
\(=\frac{1}{2}+\frac{1}{2}\)
\(=1\)
a, \(\frac{1}{15}\)+ \(\frac{4}{15}\)+ \(\frac{5}{18}\)+ \(\frac{7}{18}\)= ( \(\frac{1}{15}\)+ \(\frac{4}{15}\)) + ( \(\frac{5}{18}\)+ \(\frac{7}{18}\))
= \(\frac{1}{3}\)+ \(\frac{2}{3}\)
= \(\frac{3}{3}\)= 1
b,\(\frac{1}{8}\)+ \(\frac{1}{12}\)+ \(\frac{3}{8}\)+ \(\frac{5}{12}\)= ( \(\frac{1}{8}\)+ \(\frac{3}{8}\)) + ( \(\frac{1}{12}\)+ \(\frac{5}{12}\))
= \(\frac{1}{2}\)+ \(\frac{1}{2}\)
= \(\frac{2}{2}\)= 1