Question

tính bằng cách hợp lý

(1/3+12/67+13/41)-(79/67-28/41)

Answer 1

\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

=\(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

\(=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

\(=\frac{1}{3}-1+1\)

\(=\frac{1}{3}\)

Answer 2

(1/3+12/67+13/41)-(79/67-28/41).    =1/3+12/613/41-79/67+28/41.        =1/3+(12/67-79/67)+(13/41+28/41) =1/3+(-1)+1=1/3+0.   =1/3