Các câu hỏi tương tự
Tính(1/4-1).(1/9-1).(1/16-1)....(1/81-1).(1/100-1)
( 1 phần 4 - 1 ) . ( 1 phần 9 - 1 ) . ( 1 phần 16 - 1 ) ..... ( 1 phần 81 -1 ) .( 1 phần 100 - 1 ) = ?
\(\left(\frac{1}{4}-1\right)\left(\frac{1}{9}-1\right)\left(\frac{1}{16}-1\right).....\left(\frac{1}{81}-1\right)\left(\frac{1}{100}-1\right)\)
Tính nhanh
\(B=\left(1-\dfrac{1}{4}\right)\left(1-\dfrac{1}{9}\right)\left(1-\dfrac{1}{16}\right)....\left(1-\dfrac{1}{81}\right)\left(1-\dfrac{1}{100}\right)\)
So sánh B với \(\dfrac{11}{21}\)
Cho M=(1\4-1)×(1\9-1)×(1\16-1)×...×(1\81-1)×(1\100-1)
So sanh M voi -11\21
a, tính
C=(1/4-1)*(1/4-1)*(1/9-1)*(1/16-1)*...*(1/81-1)*(1/100-1)
Từ đó tính P=(1/2^2-1*(1/3^2-1)*...(1/20^2-1)
b ) tính M=(-1\(\frac{1}{2}\)) *(-1\(\frac{1}{3}\))*...*(-1\(\frac{1}{2014}\))
Tính :
\(A=\left(\frac{1}{4}-1\right).\left(\frac{1}{9}-1\right).\left(\frac{1}{16}-1\right)....\left(\frac{1}{81}-1\right).\left(\frac{1}{100}-1\right)\)
Helpppp me :((((
A=(\(\frac{1}{4}\)-1).(\(\frac{1}{9}\)-1).(\(\frac{1}{16}\)-1)...(\(\frac{1}{81}\)-1).(\(\frac{1}{100}\)-1)
Tính A?
\(\left(\frac{1}{4}-1\right)\left(\frac{1}{9}-1\right)\left(\frac{1}{16}-1\right)...\left(\frac{1}{81}-1\right)\left(\frac{1}{100}-1\right)\)