Question

Tính A=\(\frac{\left(3.4.6^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

Answer 1

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Answer 2

\(\frac{\left(3.4.6^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{\left(3^2.4^2.6^{32}\right)}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^4.2^{32}.3^{32}}{11.2^{35}-2^{36}}=\frac{3^{34}.2^{36}}{2^{35}.\left(11-2\right)}=\frac{3^{34}.2}{9}\)

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Answer 3

\(\frac{\left(3.4.6^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.2^4.6^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^4.2^{32}.3^{32}}{11.2^{35}-2^{36}}\)

\(=\frac{3^{34}.2^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{3^{34}.2}{9}\)

\(=\frac{3^{34}.2}{3^2}\)

\(=3^{34-2}.2\)

\(=3^{32}.2\)