Tính giá trị của các biểu thúc sau:
a) \(\frac{20^5.5^{10}}{100^5}\) c)\(\frac{6^3+3.6^2+3^3}{-13}\)
b) \(\frac{\left(0,9\right)^5}{\left(0,3\right)^6}\) d) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
Tình hợp lý;:
a) \(\frac{6^3+3.6^2+3^3}{-13}\)
b) \(\frac{2^3+3.2^6-4^3}{2^3+3^2}\)
c) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
d) \(\frac{5^5.20^3-5^4.20^3+5^7.4^5}{\left(20+5\right)^3.4^5}\)
plzz Helpppp:<<<
\(^{\left(\frac{5^4-5^3}{125^4}\right)^3}\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{\left(-0,7\right)^2.\left(-5\right)^3}{\left(-2\frac{1}{3}\right)^3.\left(1\frac{1}{2}\right)^4.\left(-1\right)^5}\)
\(\frac{20^5.5^{10}}{100^5}.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\left(\frac{4}{9}+\frac{1}{3}\right)^2+\left(\frac{3}{4}\right)^3:\left(\frac{3}{4}\right)^2:\left(\frac{-2}{3}\right)^3\)
1) Tính:
a) \(\frac{6^3-3.6^2+3^2}{-13}\)
b) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
2) Tìm n \(\in\)Z:
a) 27n : 3n = 9
b) \(\frac{25}{5^n}=5\)
c) \(\left(\frac{1}{3}\right)^n=\frac{1}{81}\)
d) \(\frac{-512}{343}=\left(\frac{-8}{7}\right)^n\)
a) \(\frac{20^5.5^{10}}{100^5}\)b)\(\frac{0,9^5}{0,3^6}\)
c)\(\frac{6^3+3.6^2+3^3}{-13}\)
d)\(\frac{4^6:9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
Giúp mình với nha!!!!!!!!!!!!!!
1) Tinh gia tri cua bieu thuc:
A=\(\frac{\left(1+2+...+100\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}\right)\left(2,4.42-21.4,8\right)}{1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
B=\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\)
Bài 1: Tính giá trị các biểu thức sau
a, \(\left[2^{-3}-\left(\frac{3}{4}\right)^{-4}.\left(-\frac{1}{2}\right)^2\right]:\left[5-3.\left(\frac{4}{15}\right)^0\right]^{-2}\)
b, \(\frac{5^5.20^3-5^4.20^3+5^7.4^5}{\left(20+5\right)^3.4^5}\)
c, \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
d, \(\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)
Tính A = \(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)