Question

tính A=[(\(\frac{2}{193}\)-\(\frac{3}{386}\)).\(\frac{193}{17}\)+\(\frac{33}{34}\)]:[(\(\frac{7}{1931}\)+\(\frac{11}{3862}\)).\(\frac{1931}{25}\)+\(\frac{8}{9}\)

Answer 1

Lương Thị Ngân Hà

\(A=\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\)\(\left[\left(\frac{7}{1931}+\frac{11}{3862}\right).\frac{1931}{25}+\frac{8}{9}\right]\)

\(\Rightarrow A=\left[\left(\frac{2}{193}.\frac{193}{17}\right)-\left(\frac{3}{386}.\frac{193}{17}\right)+\frac{33}{34}\right]\)\(:\left[\left(\frac{7}{1931}.\frac{1931}{25}\right)+\left(\frac{11}{3862}.\frac{1931}{25}\right)+\frac{8}{9}\right]\)

\(\Rightarrow A=\left[\frac{2}{17}-\frac{3}{34}+\frac{33}{34}\right]:\left[\frac{7}{25}+\frac{11}{50}+\frac{8}{9}\right]\)

\(\Rightarrow A=\left[\frac{4}{34}-\frac{3}{34}+\frac{33}{34}\right]:\left[\frac{126}{450}+\frac{99}{450}+\frac{400}{450}\right]\)

\(\Rightarrow A=1:\frac{625}{450}\)

\(\Rightarrow A=1.\frac{25}{18}=\frac{25}{18}\)

Vậy \(A=\frac{25}{18}\)

Answer 2

[(71931 +113862 ).193125 +89 ]

⇒A=[(2193 .19317 )−(3386 .19317 )+3334 ]:[(71931 .193125 )+(113862 .193125 )+89 ]

⇒A=[217 −334 +3334 ]:[725 +1150 +89 ]

⇒A=[434 −334 +3334 ]:[126450 +99450 +400450 ]

⇒A=1:625450 

⇒A=1.2518 =2518 

Vậy A=2518 

 

Answer 3

1000-100=                                         ai giải được câu này mình sẽ bái phục