Các câu hỏi tương tự
Tính:(101+100+99+98+...+3+2+1)/(101-100+99-98+...+3-2+1)
Tính nhanh:
(124.237+152):(870+235.122)
(101+100+99+...+3+2+1)/(101-100+99-98+...+3-2+1)
Tính
a, A=\(\frac{101-100+99-98+...+3-2+1}{101+100+99+98+...+3+2+1}\)
b, B=\(\frac{423133.846267+423134}{423134.846267-423133}\)
Tính A biết
A=1×2+3×4+...+98×99+100×101
A=101-100+99-98+...+3-2+1
Tính nhanh :B=1*4/2*3+2*5/3*4+...+98*101/99*100
Afrac{1}{3}-frac{2}{3^2}+frac{3}{3^3}-...+frac{99}{3^{99}}-frac{100}{3^{100}}Rightarrow3A1-frac{2}{3}+frac{3}{3^2}-...+frac{99}{3^{98}}-frac{100}{3^{99}}Rightarrow3A+Aleft(...right)+left(...right)Rightarrow4A1-frac{1}{3}+frac{1}{3^2}-...-frac{1}{3^{99}}-frac{100}{3^{100}}Rightarrow3.4A3-1+frac{1}{3}-...-frac{1}{3^{98}}-frac{100}{3^{99}}Rightarrow12A+4Aleft(...right)+left(...right)Rightarrow16A3-frac{101}{3^{99}}-frac{100}{3^{100}} 3Rightarrow A frac{3}{16}
Đọc tiếp
\(A=\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-...+\frac{99}{3^{99}}-\frac{100}{3^{100}}\)
\(\Rightarrow3A=1-\frac{2}{3}+\frac{3}{3^2}-...+\frac{99}{3^{98}}-\frac{100}{3^{99}}\)
\(\Rightarrow3A+A=\left(...\right)+\left(...\right)\)
\(\Rightarrow4A=1-\frac{1}{3}+\frac{1}{3^2}-...-\frac{1}{3^{99}}-\frac{100}{3^{100}}\)
\(\Rightarrow3.4A=3-1+\frac{1}{3}-...-\frac{1}{3^{98}}-\frac{100}{3^{99}}\)
\(\Rightarrow12A+4A=\left(...\right)+\left(...\right)\)
\(\Rightarrow16A=3-\frac{101}{3^{99}}-\frac{100}{3^{100}}< 3\)
\(\Rightarrow A< \frac{3}{16}\)
Tính Giá Trị của biểu thức sau biết ;
S = 1 /1 . 2 . 3 . 4 + 1 / 2 . 3 . 4 . 5 +......................+ 1 / 98 . 99 . 100 . 101
tính tổng:
1+2+3-4-5-6+7+8+9-10-11-12+.....+97+98+99-100-101-102