a,\(\frac{1.1.2.2.3.3....99.99.100.100}{1.2.2.3.3.4...99.100.100.101}\)=\(\frac{\left(1.2.3...99.100\right)\left(1.2.3...99.100\right)}{\left(1.2.3.4...99.100\right)\left(2.3.4...100.101\right)}\)=\(\frac{1.1}{101}\)=\(\frac{1}{101}\). ý b làm tương tự nha
Tính:
a) \(\frac{1^2}{1.2}.\frac{2^2}{2.3}.\frac{3^2}{3.4}...\frac{99^2}{99.100}.\frac{100^2}{100.101}\)
b)\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{59^2}{58.60}\)
giup mik voi help
bai 1 thuc hien phep tinh
\(\frac{1^2}{1.2}\).\(\frac{2^2}{2.3}\).\(\frac{3^2}{3.4}\)....\(\frac{99^2}{99.100}\).\(\frac{100^2}{100.101}\)
\(\frac{2^2}{1.3}\). \(\frac{3^2}{2.4}\). \(\frac{4^2}{3.5}\)... \(\frac{59^2}{58.60}\)
\(\frac{1^2}{1.2}.\frac{2^2}{2.3}.\frac{3^{^2}}{3.4}...\frac{99^2}{99.100}.\frac{100^2}{100.101}\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}...\frac{59^2}{58.60}\)
Tính:
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}....\frac{59^2}{58.60}=\)
\(\frac{2^2}{1.3}.\frac{3^2}{2.4}.\frac{4^2}{3.5}.....\frac{59^2}{58.60}\)
\(\frac{x}{200}=\frac{1^2}{1.2}.\frac{2^2}{2.3}...\frac{99^2}{99.100}\) tìm x nha
\(\frac{x}{101}=\frac{2^2}{1.3}.\frac{3^2}{2.4}...\frac{100^2}{99.101}\)
tính
\(\frac{2^2}{1.3}\).\(\frac{3^2}{2.4}\).\(\frac{4^2}{3.5}\)...\(\frac{59^2}{58.60}\)
Tính
\(\frac{1^2}{1.2}+\frac{2^2}{2.3}+\frac{3^2}{3.4}...\frac{100^2}{100.101}\)
