\(D=\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(D=\frac{37.101.43-43.101.37}{2+4+6+...+100}\)
\(D=\frac{37.\left(101.43-43.101\right)}{2+4+6+...+100}\)
\(D=\frac{37.0}{2+4+6+...+100}\)
\(D=\frac{0}{2+4+6+...+100}=0\)
Vậy \(D=0\)
Tính :
a) \(A=\frac{101+100-99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b) \(B=\frac{3737.43-4343.37}{2+4+6+...+100}\)
tính
a. A= 101+100+99+98+....+3+2+1/101-100+99-98+...+3-2+1
b,B= 3737.43-4343.37/2+4+6+...+100
Tính nhanh
a)A=\(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b)\(\frac{3737.43-4343.37}{2+4+6+...+100}\)
\(A =\)\(\dfrac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
\(B=\) \(\dfrac{3737.43-4343.37}{2+4+6+...+100}\)
Làm cách lớp 6 thôi ah
B=3737.43 - 4343.37 /2+4+6+...+100
C=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
Các bạn tính giùm mình với
1. Tính :
A= 101+100+99+98+..+3+2+1 / 101-100+99-98+..+3-2+1
B= 3737.43-4343.37/ 2+4+6+...+100
ai giải được mk sẽ tick cho
a. A= (101+100+99+98+97+....+3+2+1) : (101-100+99-98+....+3-2+1)
b, B=(3737.43 -4343.37) : (2+4+6+....+100)
Tính:
a) \(A=\frac{101+100+99+98+........+3+2+1}{101-100+99-98+.........+3-2+1}\)
b) \(B=\frac{3737.43-4343.37}{2+4+6+.........+100}\)
Tính:
a, A =\(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
b, B = \(\frac{3737.43-4343.37}{2+4+6+...+100}\)
c, D = \(\frac{2^{12}.13+2^{12}.65}{2^{10}.104}+\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)
(Các bn giải chi tiết giúp mik nha)
