Có 2 = 2
4 = 2 x 2
8 = 2 x 2 x 2
16 = 2 x 2 x 2 x 2
...........
=> Số thứ 10 = 2 x 2 x 2 x 2 x......x 2 (10 số 2) = 1024
=> A = \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{1024}\)
2A = \(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{512}\)
2A - A = \(1-\frac{1}{1024}\)
=> A = \(\frac{1023}{1024}\)