\(3\frac{1}{1117}.\frac{4}{1119}-1\frac{1116}{1117}.5\frac{1118}{1119}-\frac{5}{1119}\)
\(=\frac{3352}{1117}.\frac{4}{1119}-\frac{2233}{1117}.\frac{6713}{1119}-\frac{5}{1119}\)
\(=\frac{1}{1119}\left(\frac{3352}{1117}.4-\frac{2233}{1117}.6713-5\right)\)
\(=\frac{1}{1119}\left(\frac{13408}{1117}-\frac{14990129}{1117}-\frac{5585}{1117}\right)\)
\(=\frac{1}{1119}.\frac{-14982306}{1117}\)
\(=\frac{-14982306}{1249923}\)
Đặt \(x=\frac{1}{1117}\) ,\(y=\frac{1}{1119}\)
Khi đó biểu thức có dạng \((3+x).4y-\left(1+1-x\right).\left(5+1-y\right)-5.y\)
\(=12y+4xy-\left(2-x\right)\left(6-y\right)-5y\)
\(=12y+4xy-\left(12-6x-2y+xy\right)-5y\)
\(=9y+3xy-12+6x\)
\(=\frac{9}{1119}+\frac{3}{1117.1119}-12+\frac{6}{1117}\)
\(=\frac{9.1117+3-12.1117.1119+6.1119}{1117.1119}\)
Ưm đến đây tự tính nha =)
