2a/3b+3b/4c+4c/5d+5d/2a biet 2a/3b=3b/4c=4c/5d=5d/2a
=>\(\frac{2a}{3b}+\frac{3b}{4c}+\frac{4c}{5d}+\frac{5d}{2a}=\frac{2ax3bx4cx5d}{2ax3bx4cx5b}=1\)
=>1--1,4=-4
=> -4 hoac 4
Câu 1 Tính giá trị biểu thức
2a/3b+3b/4c+4c/5d+5d/2a
Biết 2a/3b=3b/4c=4c/5d=5d/2a
Mình đang cần gấp!Cảm ơn nhiều!
2a/3b+3b/4c+4c/5d+5d/2a biet 2a/3b=3b/4c=4c/5d=5d/2a
C=2a/3b+3b/4c+4c/5d+5d/2a biet 2a/3b=3b/4c=4c/5d=5d/2a
2a/3b.3b/4c.4b/5d.5d/2a biet 2a/3b=3b/4c=4c/5d=5d/2a
Tinh
2a/3b+3b/4c+4c/5d+5d/2a
Biet 2a/3b=3b/4c=4c/5d=5d/2a
Bài 1 : Tinh
B = 2a/3b + 3b/4c + 4c/5d + 5d/2a biet 2a/3b = 3b/4c=4c/5d = 5d/2a
Tính 2a/3b + 3b/4c + 4c/5d + 5d/2a biết 2a/3b=3b/4c=4c/5d=5d/2a
Tính :
\(\frac{2a}{3b}+\frac{3b}{4c}+\frac{4c}{5d}+\frac{5d}{2a}\) biết \(\frac{2a}{3b}=\frac{3b}{4c}=\frac{4c}{5d}=\frac{5d}{2a}\)
giúp mình nha !
Tính C = 2a/3b + 3b/4c + 4c/5d + 5d/2a.Biết 2a/3b = 3b/4c = 4c/5d = 5d/2a.
