\(\frac{1}{2}+\frac{1}{4}+\frac{1}{16}+\frac{1}{32}\)
\(=\frac{16}{32}+\frac{8}{32}+\frac{2}{32}+\frac{1}{32}\)
\(=\frac{16+8+2+1}{32}\)
\(=\frac{27}{32}\)
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