Question

Tính 1 cách hợp lí:

a, 4.{3^2.[(5^2+2^3):11]-26}+2002

 

Answer 1

Trả lời :

\(a,4.\left\{3^2.\left[\left(5^2+2^3\right):11\right]-26\right\}+2002\)

\(=4.\left\{9.\left[\left(25+8\right):11\right]-26\right\}+2002\)

\(=4.\left\{9.\left[33:11\right]-26\right\}+2002\)

\(=4.\left\{9.3-26\right\}+2002\)

\(=4.1+2002\)

\(=2006\)

Hok_tốt

#Thiên_Hy

Answer 2

\(4.\left\{3^2.\left[\left(5^2+2^3\right):11\right]-26\right\}+2002\)

\(=4.\left\{9.\left[\left(25+8\right):11\right]-26\right\}+2002\)

\(=4.\left\{9.\left[33:11\right]-26\right\}+2002\)

\(=4.\left\{9.3-26\right\}+2002\)

\(=4.\left\{27-26\right\}+2002\)

\(=4.1+2002\)

\(=4+2002\)

\(=2006\)

~ Hok tốt ~

Answer 3

4.{3^2[(5^2+2^3):11]-26}+2002

=4.{9[(25+8):11]-26}+2002

=4.{9.33:11]-26}+2002

=4.{[297:11]-26}+2002

=4.{ 27 -16}+2002

=4.1+2002

=2+2002

=2008