\(\dfrac{7}{12}+x=\dfrac{3}{2}\)
\(\Rightarrow x=\dfrac{3}{2}-\dfrac{7}{12}\)
\(\Rightarrow x=\dfrac{18}{12}-\dfrac{7}{12}\)
\(\Rightarrow x=\dfrac{11}{12}\)
Vậy: \(x=\dfrac{11}{12}\)
\(\dfrac{7}{12}+x=\dfrac{3}{2}=>x=\dfrac{3}{2}-\dfrac{7}{12}=\dfrac{18}{12}-\dfrac{7}{12}=\dfrac{11}{12}\)