Question

Tìm:a,2n+2 chia hết cho 2n-1

       b,2n-5 chia hết cho n+3

Answer 1

a)\(2n+2⋮2n-1\)

\(\Rightarrow2n-1+3⋮2n-1\)

\(\Rightarrow3⋮2n-1\)

\(\Rightarrow2n-1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)

\(\Rightarrow2n-1=1;-1;3;-3\)

\(\Rightarrow2n=2;0;4;-2\)

\(\Rightarrow n=1;0;2;-1\)

Answer 2

b)\(2n-5⋮n+3\)

\(\Rightarrow2\left(n+3\right)-11⋮n+3\)

\(\Rightarrow11⋮n+3\)

\(\Rightarrow n+3\inƯ\left(11\right)=\left\{\pm1;\pm11\right\}\)

\(\Rightarrow n+3=1;-1;11;-11\)

\(\Rightarrow n=-2;-4;8;-14\)

Answer 3

Mình k đây nè,lần sau nhớ k cho mình nhé

Answer 4

Có ai bt viết dấu chia hết ko ??? Chỉ cho mk vs, mk ko bt .