\(y+y\cdot8=\frac{648}{9}\)
\(y\left(1+8\right)=72\)
\(9y=72\)
\(y=\frac{72}{9}\)
\(y=8\)
Vậy y = 8
ta có y+8Xy=648/9
=>9Xy=72
=>y=72/9=8
Vậy y=8
ta có
y + 8 Xy = 648/9
=>9Xy=72
=>y=72/9=8
vậy y =8
ta có :
y + 8Xy = 648/9
=> 9Xy = 72
=> y = 72/9 = 8
vậy y = 8