Ta có : \(y:\frac{1}{10}-y:4-y:\frac{3}{4}=2,25\)
\(\Leftrightarrow y.10-y.\frac{1}{4}-y.\frac{4}{3}=2,25\)
\(\Leftrightarrow y\left(10-\frac{1}{4}-\frac{4}{3}\right)=2,25\)
\(\Leftrightarrow y.\frac{101}{12}=\frac{27}{12}\)
\(y=\frac{27}{12}:\frac{101}{12}=\frac{27}{101}\)
Vậy y=\(\frac{27}{101}\)