Ta có: \(\frac{y}{3}+y\cdot\frac{2}{3}=\frac{y}{12}+\frac{11}{6}\)
=> \(\frac{y}{3}+\frac{2y}{3}=\frac{y}{12}+\frac{22}{12}\)
=> \(\frac{y+2y}{3}=\frac{y+22}{12}\)
=> \(\frac{3y}{3}=\frac{y+22}{12}\)
=> \(y=\frac{y+22}{12}\)
=> y + 22 = 12y
=> y - 12y = 22
=> -11y = 22
=> y = 22 : (-11) = -2
Vậy y = -2