Question

Tìm y biết:(\(\frac{5}{7}-y\)) x \(\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

Answer 1

(\(\frac{5}{7}-y\)) x \(\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y\)            = \(\frac{6}{5}:\frac{14}{5}\)

\(\frac{5}{7}-y\)             = \(\frac{3}{7}\)

            y                 = \(\frac{5}{7}-\frac{3}{7}\)

           y                  = \(\frac{2}{7}\)

Answer 2

\(\left(\frac{5}{7}-y\right)\cdot\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\Leftrightarrow\left(\frac{5}{7}-y\right)\cdot\frac{14}{5}=\frac{7}{10}+\frac{5}{10}\)

\(\Leftrightarrow\left(\frac{5}{7}-y\right)\cdot\frac{14}{5}=\frac{6}{5}\)

\(\Leftrightarrow\frac{5}{7}-y=\frac{6}{5}\div\frac{14}{5}\)

\(\Leftrightarrow\frac{5}{7}-y=\frac{3}{7}\)

\(\Rightarrow y=\frac{5}{7}-\frac{3}{7}=\frac{2}{7}\)

Answer 3

Nên tự tính 

Nếu thik thì lấy máy tính tính cho nhanh nha bạn

Answer 4

\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}+\frac{5}{10}\)

\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{12}{10}\)

\(\frac{5}{7}-y=\frac{12}{10}:\frac{14}{5}\)

\(\frac{5}{7}-y=\frac{12}{10}\times\frac{5}{14}\)

\(\frac{5}{7}-y=\frac{3}{7}\)

\(y=\frac{5}{7}-\frac{3}{7}\)

\(y=\frac{2}{7}\)

Answer 5

y=2/7       nha.

Answer 6

\(\left(\frac{5}{7}-y\right)\times\frac{14}{5}=\frac{7}{10}+\frac{1}{2}\)

\(\frac{5}{7}-y\times\frac{14}{5}=\frac{6}{5}\)

\(\frac{5}{7}-y=\frac{6}{5}:\frac{14}{5}\)

\(y=\frac{5}{7}-\frac{3}{7}\)

\(y=\frac{2}{7}\)

Answer 7

(5/7-y).14/5=5/6

5/7-y=5/6:14/5

5/7-y=25/84

y=5/7-25/84

y=5/12