\(\frac{12-y}{y}=\frac{4}{3}\Rightarrow\frac{y=8}{y=3}\)\
Vậy...
=> \(\frac{12-y}{y}=\frac{4}{3}\) => \(\frac{12}{y}-1=\frac{4}{3}\) => \(\frac{12}{y}=\frac{4}{3}+1\) => \(\frac{12}{y}=\frac{7}{3}\) => y = 12 : \(\frac{7}{3}\) => y=\(\frac{36}{7}\)
\(\frac{12-y}{y}=\frac{2}{3}:\frac{1}{2}\)
\(\frac{12-y}{y}=\frac{2}{3}.\frac{2}{1}\)
\(\frac{12-y}{y}=\frac{4}{3}\)
\(\Rightarrow3\left(12-y\right)=4y\)
\(\Rightarrow36-3y=4y\)
\(\Rightarrow4y+3y=36\)
\(\Rightarrow7y=36\)
\(\Rightarrow y=\frac{36}{7}\)
\(\frac{12-y}{y}=\frac{2}{3}:\frac{1}{2}\)
\(\frac{12-y}{y}=\frac{2}{3}\times\frac{2}{1}\)
\(\frac{12-y}{y}=\frac{4}{3}\)
\(\Rightarrow\left(12-y\right)\times3=4\times y\)
\(\Rightarrow36-3y=4y\)
\(\Rightarrow4y+3y=36\)
\(\Rightarrow7y=36\)
\(\Rightarrow y=\frac{36}{7}\)
mấy bạn cho mình hỏi sao
\(\frac{3}{2}:\frac{1}{2}=\frac{4}{3}\) đáng lẽ phải là như zầy chớ \(\frac{3}{2}x\frac{2}{1}=\frac{6}{2}=3\)
vo tran huyen tran hỏi sai kìa: 2/3 chứ ko phải 3/2