\(a,\dfrac{5}{y}=\dfrac{1}{2}\)
\(\dfrac{5}{y}=\dfrac{5}{10}\)
\(\Rightarrow y=10\)
\(b,\dfrac{42}{25}:\dfrac{y}{5}=\dfrac{6}{5}\)
\(\dfrac{y}{5}=\dfrac{42}{25}:\dfrac{6}{5}\)
\(\dfrac{y}{5}=\dfrac{7}{5}\)
\(\Rightarrow y=7\)
\(a)\dfrac{5}{y}=\dfrac{1}{2}<=>\dfrac{5}{10}=\dfrac{1}{2} nên => \dfrac{5}{y}=\dfrac{5}{10}=y=10\)
\(b)\dfrac{42}{25}:\dfrac{y}{5}=\dfrac{6}{5}\)
\(\dfrac{y}{5}=\dfrac{42}{25}:\dfrac{6}{5}\)
\(\dfrac{y}{5}=\dfrac{7}{5}<=>y=7\)