Question

Tim x,y,z:\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)   và 2x+3y-z=95

Answer 1

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)

Theo tính chất dãy tỉ số bằng nhau , ta có :

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)\(=\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}\)

\(\frac{2x-2}{4}+\frac{3y-6}{9}-\frac{z-3}{4}\)\(=\frac{95}{9}\)

=> \(x=\frac{190}{9}\)\(y=\frac{95}{3}\)\(z=\frac{380}{9}\)

Answer 2

\(\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{-z+3}{-4}=\frac{2x+3y-z-5}{9}=\frac{90}{9}=10\)

x=;y=;z= tu tinh