Ta có :
\(\left|1-2x\right|+\left|2-3y\right|+\left|3-4z\right|=0\)
\(\Leftrightarrow\)\(\hept{\begin{cases}\left|1-2x\right|=0\\\left|2-3y\right|=0\\\left|3-4z\right|=0\end{cases}}\Leftrightarrow\hept{\begin{cases}1-2x=0\\2-3y=0\\3-4z=0\end{cases}}\)
\(\Leftrightarrow\)\(\hept{\begin{cases}2x=1\\3y=2\\4z=3\end{cases}\Leftrightarrow\hept{\begin{cases}x=\frac{1}{2}\\y=\frac{2}{3}\\z=\frac{3}{4}\end{cases}}}\)
Vậy \(\left(x,y,z\right)=\left(\frac{1}{2};\frac{2}{3};\frac{3}{4}\right)\)
Chúc bạn học tốt ~
Ta có: \(|1-2x|,|2-3y|,|3-4z|\ge0\)
Mà \(|1-2x|+|2-3y|+|3-4z|\)= 0
Nên \(\hept{\begin{cases}1-2x=0\\2-3y=0\\3-4z=0\end{cases}}\Leftrightarrow\hept{\begin{cases}2x=1\\3y=2\\4x=3\end{cases}}\Leftrightarrow\hept{\begin{cases}x=\frac{1}{2}\\y=\frac{2}{3}\\z=\frac{3}{4}\end{cases}}\)
Vậy \(\hept{\begin{cases}x=\frac{1}{2}\\y=\frac{2}{3}\\z=\frac{3}{4}\end{cases}}\)
