\(\frac{x-1}{2}=\frac{y=3}{4}=\frac{z-5}{6}\Rightarrow\frac{3x-3}{6}=\frac{4y+12}{16}=\frac{5z-25}{30}\)
Áp dụng tính chất dãy TSBN, ta có:
\(\frac{\left(5z-25\right)-\left(3x-3\right)-\left(4x+12\right)}{30-6-16}\)
= \(\frac{\left(5z-3x-4y\right)-\left(25-3+12\right)}{8}\)
= \(\frac{50-34}{8}\)
= \(\frac{16}{8}\)
= 2
Suy ra: \(\frac{3x-3}{6}=2\Rightarrow\frac{x-1}{2}=2\Rightarrow x=5\)
\(\frac{4y+12}{6}=2\Rightarrow\frac{y+3}{4}=2\Rightarrow y=5\)
\(\frac{5z-25}{30}=2\Rightarrow\frac{z-5}{6}=2\Rightarrow z=17\)
Vậy: x = 5
y = 5
z = 1