\(\frac{x+1}{3}=\frac{y+2}{4}=\frac{z+3}{5}\)
Áp dụng t/c dãy tỉ số bằng nhau ta có:
\(\frac{x+1}{3}=\frac{y+2}{4}=\frac{z+3}{5}=\frac{x+1+y+2+z+3}{3+4+5}=\frac{24}{12}=2\)
\(\frac{x+1}{3}=2\Rightarrow x+1=6\Rightarrow x=5\)
\(\frac{y+2}{4}=2\Rightarrow y+2=8\Rightarrow y=6\)
\(\frac{z+3}{5}=2\Rightarrow z+3=10\Rightarrow z=7\)
Vậy x=5;y=6;z=7
tim x,y,z biet:x/3=y/4,y/5=z/7 va 2x+3y-z=124
Tim x, y,z:
a/ x:y:x=\(3:5:9-\left(-2\right)\)va \(5.x-y+3.z=-16\)
b/ \(2.x=3.y;5.y=7.z\)va \(3.x-7.y+5.z=30\)
c/ x:y;z=4:5:6 va \(x^2-2.y^2+z^2=18\)
tim x, y, z
a) x/y=-6/9 va x-y=30
b)x/5=y/4, z/5=y/7 va 2*x+3*y-z=106
c)x/5=y/4=z/7 va x+2*y+z=40
x/2 = y/3 ; y/5= z/4 va x-y+z=-49 Tim x, y,z
tim x, y, z biet:
2/3.x=3/4.y=4/5.z va x+y-z=57
Tim x,z,y biet
x/2=y/3;y/4=z/5 va x+y-z=10
tim x y z x/2=y/3 y/4=z/5 va x^2-y^2=16
3x/8=3y/6y=3z/216 va 2x^2+2y^2-z^2=1
Tim x,y,z : 3(x-1)=2(y-2),4(y-2)=3(z-3) va 2x+3y-z=50
Tim x,y,z biet (x-1)/2= (y+3)/4 =(z-5)/6 va 5z-3x-4y
