nhầm đoạn cuối 54/-7 = -54/7
=> x= -216/7 ; y=-324/7 ; z= -270/7
\(\left(3x-2y\right)^{2014}\ge0\) ; \(\left|5y-6z\right|^{2015}\ge0\)
\(\Rightarrow\left(3x-2y\right)^{2014}+\left|5y-6z\right|^{2015}\ge0\)
mà \(\left(3x-2y\right)^{2014}+\left|5y-6z\right|^{2015}=0\)
\(\Rightarrow\left(3x-2y\right)^{2014}=\left|5y-6z\right|^{2015}=0\Rightarrow3x-2y=5y-6z=0\)
\(\Rightarrow3x=2y;5y=6z\)
\(3x=2y\Rightarrow\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{4}=\frac{y}{6}\left(1\right)\)
\(5y=6z\Rightarrow\frac{y}{6}=\frac{z}{5}\left(2\right)\)
Từ \(\left(1\right)\) và \(\left(2\right)\) \(\Rightarrow\frac{x}{4}=\frac{y}{6}=\frac{z}{5}=\frac{2x}{8}=\frac{5y}{30}=\frac{3z}{15}=\frac{2x-5y+3z}{8-30+15}=\frac{54}{-7}=-\frac{7}{54}\) [áp dụng dãy tỉ số bằng nhau]
=> x= -14/27 ; y= -7/9 ; z= -35/51
