Question

tìm x,y,z biết

\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}zvà-x+z=-196\)

b, 2x=3y=5x=> I x+y-zI=96

Answer 1

\(\frac{x}{\frac{11}{6}}=\frac{y}{\frac{2}{9}}=\frac{z}{\frac{5}{18}}=\frac{-x+z}{-\frac{11}{6}+\frac{5}{18}}=-\frac{196}{-\frac{14}{9}}=126\)

x=\(126.\frac{11}{6}=231\)

y=\(126.\frac{2}{9}=28\)

z=\(126.\frac{5}{18}=35\)

b) \(\frac{x}{15}=\frac{y}{10}=\frac{z}{6}=\frac{x+y-z}{15+10-6}=\frac{96}{19}\)hoặc \(\frac{x}{15}=\frac{y}{10}=\frac{z}{6}=\frac{x+y-z}{15+10-6}=-\frac{96}{19}\)

=> ...........