\(\frac{12}{-6}=\frac{x}{5}\Rightarrow x=\frac{12.5}{-6}=\frac{2.3.2.5}{-1.2.3}=\frac{2.5}{-1}=\frac{10}{-1}=-10\)
\(\frac{-10}{5}=\frac{-y}{3}\Rightarrow-y=\frac{-10.3}{5}=\frac{-1.2.5.3}{5}=\frac{-1.2.3}{1}=\frac{-6}{1}=-6\Rightarrow y=6\)
\(\frac{-6}{3}=\frac{z}{-7}\Rightarrow z=\frac{-6.\left(-7\right)}{3}=\frac{-2.3.\left(-7\right)}{3}=\frac{-2.\left(-7\right)}{1}=14\)
Vậy x = 10 ; y = 6 ; z = 14
Ta có:\(\frac{12}{-6}=\frac{-60}{30}=\frac{-10}{5}=\frac{-6}{3}=\frac{-42}{21}=\frac{14}{-7}\)
=>x=-10
-y=-6
z=14
=>x=-10
y=6
z=14
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