Question

Tìm x,y,z biết: \(\frac{x-1}{2}\)=\(\frac{y-2}{3}\)=\(\frac{z-3}{4}\)và 2x + 3y - z = 50

Answer 1

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}=>\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}\)

áp dụng .. ta có :

\(\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}=\frac{2x-2+3y-6-z+3}{4+9-4}=\frac{\left(2x+3y-z\right)-2-6+3}{9}=\frac{50-2-6+3}{9}=\frac{45}{9}=5\)

=>x-1/2=5=>x-1=10=>x=9

=>y-2/3=5=>y-2=15=>y=13

=>z-3/4=5=>z-3=20=>z=17

Answer 2

quên mất kết quả là :

=>x-1/2=5=>x-1=10=>x=11

=>y-2/3=5=>y-2=15=>y=17

=>z-3/4=5=>z-3=20=>z=23 

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