Question

Tìm x,y,z biết 2x+3y-xy=8

Answer 1

\(2x+3y-xy=8\)

\(\Rightarrow2x+3y-xy-6=2\)

\(\Rightarrow x\left(2-y\right)-3\left(2-y\right)=2\)

\(\Rightarrow\left(x-3\right)\left(2-y\right)=2\)

Answer 2

2x+3y-xy=8

2x+3y-xy-6=2

x(2-y)+3(2-y)=2

(x+3)(2-y)=2

Answer 3

$2x+3y-xy=8$

$\Rightarrow 2x+3y-xy-6=2$

$\Rightarrow x\left(2-y\right)-3\left(2-y\right)=2$

$\Rightarrow \left(x-3\right)\left(2-y\right)=2$

⇒(x−3)(2−y)= 2 . 1=1. 2 = -1 .-2= -2 .-1

⇒(x,y)= {(5;2),(3;0),(2;4),(1;3)}