\(2x=3y\Rightarrow\frac{x}{3}=\frac{y}{2}\Rightarrow\frac{x}{6}=\frac{y}{4}\)
\(2y=4z\Rightarrow\frac{y}{4}=\frac{z}{2}\)
\(\Rightarrow\frac{x}{6}=\frac{y}{4}=\frac{z}{2}=\frac{x-y+z}{6-4+2}=\frac{18}{4}\)
=>x=27;y=18;z=9
vậy x=27;y=18;z=9
\(2x=3y\Rightarrow\frac{y}{2}=\frac{x}{3}\)
\(2y=4z\Rightarrow\frac{z}{2}=\frac{y}{4}\Rightarrow\frac{z}{1}=\frac{y}{2}\)
\(\frac{x}{3}=\frac{y}{2}=\frac{z}{1}\)
áp dụng tính chất dãy tỉ số bằng nhau
\(\frac{x}{3}=\frac{y}{2}=\frac{z}{1}=\frac{x+y+z}{3+2+1}=\frac{18}{6}=3\)
\(\Rightarrow\frac{x}{3}=3\Rightarrow x=9\)
\(\Rightarrow\frac{y}{2}=3\Rightarrow y=6\)
\(\Rightarrow z=3\)
