\(\frac{x-3}{y-2}=\frac{3}{2}\)
\(\Rightarrow\left(x-3\right).2=\left(y-2\right).3\)
\(\Leftrightarrow2x-6=3y-6\)
\(\Rightarrow2x=3y\)
\(\Rightarrow2x-2y=y\)
\(\Rightarrow2.\left(x-y\right)=y\)
Mà \(x-y=4\)
\(\Rightarrow2.4=y\)
\(\Rightarrow y=8\)
thay y vào ta được :
\(2x=3.8\)
\(\Rightarrow x=\frac{3.8}{2}=12\)
vậy \(x=12\); \(y=8\)