\(\frac{x-4}{y-3}=\frac{4}{3}\)
=> 3.(x-4) = 4.(y-3)
=> 3x-12 = 4y-12
=> 3x = 4y
=> \(\frac{x}{4}=\frac{y}{3}\)
Theo t/c dãy TSBN:
\(\frac{x}{4}=\frac{y}{3}=\frac{x-y}{4-3}=\frac{5}{1}=5\)
=> x/4 = 5 => x = 5.4 = 20
=> y/3 = 5 => y = 5.3 = 15
Vậy x = 20; y = 15.