Question

tìm x;y thuộc N biết (x+1).(2y-5)

Answer 1

pt \(\Rightarrow\)\(\orbr{\begin{cases}x+1=0\\2y-5=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\y=\frac{5}{2}\end{cases}}}\)

Answer 2

\(pt\orbr{\begin{cases}x+1=0\\2y-5=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\y=\frac{5}{2}\end{cases}}}\)

Answer 3

( x+1). ( 2y-5) => ( x+1) = ( 2y-5)=0

x+1 = 0  => x=-1

2y-5= 0 => 2y=5 => y=2,5

Answer 4

\(\left(x+1\right)\left(2y-5\right)=0\)

\(=>\orbr{\begin{cases}x+1=0\\2y-5=0\end{cases}=>\orbr{\begin{cases}x=-1\\y=\frac{5}{2}\end{cases}}}\)