ta co : 1+2y/18=1+4y/24
=> 24(1+2y)=18(1+4y)
=>24+48y=18+72y
=>24-18=72y-48y
=>6=24y
=>y=1/4
thay y thanh 1/4 vao de bai ta co :
1+1/2/18=1+1/24=(1+3/2)/6x
=>1/12=(5/2)/6x
=>12/(5/2)=6x
=>30=6x/x=5
vay x=5 va y=1/4
Tìm x,y:
1+2y:18=1+4y:24=1+6y:(6x)
Tìm x; y ;z biết 1+2y/18=1+4y/24=1+6y/6x
tìm x,y :
1+2y/18 = 1+4y/24 = 1+6y/6x
Tìm x , y biết :
1 + 2y / 18 = 1 + 4y / 24 = 1 + 6y / 6x
Tìm x, y biết rằng: \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
Tìm x,y biết rằng :
1+2y/18=1+4y/24=1+6y/6x
tìm x,y,z: biết (1+2y)/18=(1+4y)/24=(1+6y)/6x=(1+8y)/(27z)
Tìm x,y,z bít (1+2y)/18=(1+4y)/24=(1+6y)/6x=(1+8y)/27z
Tìm x biết: (1+2y)/18=(1+4y)/24=(1+6y)/6x
